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代写EME 150A,SQ, 2024 Homework 5代做迭代
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EME 150A,SQ, 2024
Homework 5
1- This problem illustrates that the factor of safety for a machine element depends on the particular point selected for analysis. Here you are to compute factors of safety, based upon the distortion-energy theory, for stress elements at A and B of the member shown in the figure. This bar is made of AISI 1006 cold-drawn steel and is loaded by the forces F = 0.55 kN, P = 4.0 kN, and T = 25 N ∙ m. (Find material properties in Table A-20 of the book)
2- The figure shows a shaft mounted in bearings at A and D and having pulleys at B and C.
The forces shown acting on the pulley surfaces represent the belt tensions. The shaft is to be made of AISI 1035 CD steel. Using a conservative failure theory with a design factor of 2, determine the minimum shaft diameter to avoid yielding. (Find material properties in Table A-20 of the book)
3- An AISI 1018 steel has a yield strength, Sy = 295 MPa. Using the distortion-energy theory for the given state
of plane stress, (a) determine the factor of safety, (b) plot the failure locus, the load line, and estimate the factor of safety by graphical measurement.
4- An AISI 4142 steel Q&T at 800°F exhibits Syt = 235 kpsi, Syc = 285 kpsi, and εf = 0.07. For the given state of
plane stress, (a) determine the factor of safety, (b) plot the failure locus and the load line, and estimate the factor of safety by graphical measurement.